Astrus*, Wassup Rocker's ' "How Much Is a Gram of Love?" was released on its scheduled release date, August 16, 2019. How Much Is a Gram of Love? is considered explicit and may contain foul language. This song is about 3 minutes and 0 seconds, which is about the average length of a typical song. Because this song is the only song in How Much Is a Gram of Love? and no other songs are present in the album, we classify this track as a single. On top of that, Turks and Caicos Islands appears to be the country where this track was created. How Much Is a Gram of Love? is not that popular right now. The overall tone is very danceable, especially with its high energy, which produces more of a euphoric, cheerful, or happy vibe.
We consider the tempo marking of How Much Is a Gram of Love? by Astrus*, Wassup Rocker to be Andante (at a walking pace) because the track has a tempo of 81 BPM, a half-time of 40BPM, and a double-time of 162 BPM. Based on that, the speed of the song's tempo is slow. The time signature for this track is 4/4.
F♯ Minor is the music key of this track. This also means that this song has a camelot key of 11A. So, the perfect camelot match for 11A would be either 11A or 10B. While, a low energy boost can consist of either 11B or 12A. For moderate energy boost, you would use 8A and a high energy boost can either be 1A or 6A. However, if you are looking for a low energy drop, finding a song with a camelot key of 10A would be a great choice. Where 2A would give you a moderate drop, and 9A or 4A would be a high energy drop. Lastly, 2B allows you to change the mood.
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